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      1. 廣東北電的筆試題

        時間:2021-01-16 16:30:54 筆試題目 我要投稿

        廣東北電的筆試題

          1.漢譯英

        廣東北電的筆試題

          北電網絡的開發者計劃使來自于不同組織的開發者,能夠在北電網絡的'平臺上開發圓滿的補充業務。北電網絡符合工業標準的開放接口,為補充業務的開展引入了無數商機,開發者計劃為不同層面的開發者提供不同等級的資格,資格的劃分還考慮到以下因素:補充業務與北電網絡平臺的集合程度,開發者團體與北電網絡的合作關系,等等。

          答:呵呵。這個這個基本上還是不現丑了吧。

          2.編程

          將整數轉換成字符串:void itoa(int,char);

          例如itoa(-123,s[])則s=“-123”;

          答:

          char* itoa(int value, char* string)

          {

          char tmp[33];

          char* tp = tmp;

          int i;

          unsigned v;

          char* sp;

          // 將值轉為正值

          if (value < 0)

          v = -value;

          else

          v = (unsigned)value;

          // 將數轉換為字符放在數組tmp中

          while (v)

          {

          i = v % 10;

          v = v / 10;

          *tp++ = i+'0';

          }

          // 將tmp里的字符填入string指針里,并加上負號(如果有)

          sp = string;

          if (value < 0)

          *sp++ = '-';

          while (tp > tmp)

          *sp++ = *–tp;

          *sp = 0;

          return string;

          }

          英文筆試題

          1. Tranlation (Mandatory)

          CDMA venders have worked hard to give CDMA roaming capabilities via the development of RUIM-essentially, a SIM card for CDMA handsets currently being deployed in China for new CDMA operator China Unicom. Korean cellco KTF demonstrated earlier this year the ability to roam between GSM and CDMA using such cards.However,only the card containing the user’s service data can roam-not the CDMA handset or the user’s number (except via call forwarding).

          2. Programming (Mandatory)

          Linked list

          a. Implement a linked list for integers,which supports the insertafter (insert a node after a specified node) and removeafter (remove the node after a specified node) methods;

          b. Implement a method to sort the linked list to descending order.

          3. Debugging (Mandatory)

          a. For each of the following recursive methods,enter Y in the answer box if themethod terminaters (assume i=5), Otherwise enter N.

          static int f(int i){

          return f(i-1)*f(i-1);

          }

          Ansewr:

          static int f(int i){

          if(i==0){return 1;}

          else {return f(i-1)*f(i-1);}

          }

          Ansewr:

          static int f(int i){

          if(i==0){return 1;}

          else {return f(i-1)*f(i-2);}

          }

          Ansewr:

          b. There are two errors in the following JAVA program:

          static void g(int i){

          if(i==1){return;}

          if(i%2==0){g(i/2);return;}

          else {g(3*i);return;}

          }

          please correct them to make sure we can get the printed-out result as below:

          3 10 5 16 8 4 2 1

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