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      1. 思遷數(shù)碼科技招聘Java軟件工程師筆試真題

        時(shí)間:2020-12-14 10:03:34 筆試題目 我要投稿

        思遷數(shù)碼科技招聘Java軟件工程師筆試真題

          選擇題

        思遷數(shù)碼科技招聘Java軟件工程師筆試真題

          1:Which statements about Java code security are not true?

          A.The bytecode verifier loads all classes needed for the execution of a program.

          B.Executing code is performed by the runtime interpreter.

          C.At runtime the bytecodes are loaded, checked and run in an interpreter.

          D.The class loader adds security by separating the namespaces for the classes of the local file system from those imported from network sources.

          2:What is the result when you compile and run the following code?

          public class Test

          {

          public void method()

          {

          for(int i = 0; i < 3; i++)

          {

          System.out.print(i);

          }

          System.out.print(i);

          }

          }

          Choices:

          What is the result when you compile and run the following code?

          public class Test

          {

          public void method()

          {

          for(int i = 0; i < 3; i++)

          {

          System.out.print(i);

          }

          System.out.print(i);

          }

          }

          Choices:

          A.0122

          B.0123

          C.Compilation error

          D.None of these

          3:

          Give the following code:

          public class Example{

          public static void main(String args[] ){

          int l=0;

          do{

          System.out.println(“Doing it for l is:”+l);

          }while(--l>0)

          System.out.println(“Finish”);

          }

          }

          Which well be output:

          Give the following code:

          public class Example{

          public static void main(String args[] ){

          int l=0;

          do{

          System.out.println(“Doing it for l is:”+l);

          }while(--l>0)

          System.out.println(“Finish”);

          }

          }

          Which well be output:

          A.Doing it for l is 3

          B.Doing it for l is 1

          C.Doing it for l is 2

          D.Doing it for l is 0

          4:Math.round(11.5)等於多少?

          A.11

          B.12

          C.11.5

          D.none

          5:

          What will happen when you attempt to compile and run the following code?

          int Output = 10;

          boolean b1 = false;

          if((b1 == true) && ((Output += 10) == 20))

          {

          System.out.println("We are equal " + Output);

          }

          else

          {

          System.out.println("Not equal! " + Output);

          }

          Choices:

          What will happen when you attempt to compile and run the following code?

          int Output = 10;

          boolean b1 = false;

          if((b1 == true) && ((Output += 10) == 20))

          {

          System.out.println("We are equal " + Output);

          }

          else

          {

          System.out.println("Not equal! " + Output);

          }

          Choices:

          A.Compilation error, attempting to perform binary comparison on logical data type

          B.Compilation and output of "We are equal 10".

          C.Compilation and output of "Not equal! 20".

          D.Compilation and output of "Not equal! 10".

          6:

          What will happen when you attempt to compile and run the following code?

          (Assume that the code is compiled and run with assertions enabled.)

          public class AssertTest{

          public void methodA(int i){

          assert i >= 0 : methodB();

          System.out.println(i);

          }

          public void methodB(){

          System.out.println("The value must not be negative");

          }

          public static void main(String args[]){

          AssertTest test = new AssertTest();

          test.methodA(-10);

          }

          }

          What will happen when you attempt to compile and run the following code?

          (Assume that the code is compiled and run with assertions enabled.)

          public class AssertTest{

          public void methodA(int i){

          assert i >= 0 : methodB();

          System.out.println(i);

          }

          public void methodB(){

          System.out.println("The value must not be negative");

          }

          public static void main(String args[]){

          AssertTest test = new AssertTest();

          test.methodA(-10);

          }

          }

          A.it will print -10

          B.it will result in AssertionError showing the message-“the value must not be negative”.

          C.the code will not compile.

          D.None of these.

          7:

          What is the result when you compile and run the following code?

          public class ThrowsDemo

          {

          static void throwMethod()

          {

          System.out.println("Inside throwMethod.");

          throw new IllegalAccessException("demo");

          }

          public static void main(String args[])

          {

          try

          {

          throwMethod();

          }

          catch (IllegalAccessException e)

          {

          System.out.println("Caught " + e);

          }

          }

          }

          Choices:

          What is the result when you compile and run the following code?

          public class ThrowsDemo

          {

          static void throwMethod()

          {

          System.out.println("Inside throwMethod.");

          throw new IllegalAccessException("demo");

          }

          public static void main(String args[])

          {

          try

          {

          throwMethod();

          }

          catch (IllegalAccessException e)

          {

          System.out.println("Caught " + e);

          }

          }

          }

          Choices:

          A.Compilation error

          B.Runtime error

          C.Compile successfully, nothing is printed.

          D.Inside throwMethod. followed by caught:java.lang.IllegalAccessExcption: demo

          8:假定a和b為int型變量,則執(zhí)行下述語(yǔ)句組后,b的值為

          a=1;

          b=10;

          do

          {

          b-=a;

          a++;

          } while (b--<0);

          A.9

          B.-2

          C.-1

          D.8

          9:

          public class X{

          public Object m(){

          Object o = new Float(3.14F);//line 3

          Object [] oa = new Object[1];//line 4

          oa[0] = o;//line 5

          o=null;//line 6

          return oa[0];//line 7

          }

          }

          When is the Float object, created in line 3,eligible for garbage collection?

          public class X{

          public Object m(){

          Object o = new Float(3.14F);//line 3

          Object [] oa = new Object[1];//line 4

          oa[0] = o;//line 5

          o=null;//line 6

          return oa[0];//line 7

          }

          }

          When is the Float object, created in line 3,eligible for garbage collection?

          A.just after line 5.

          B.just after line 6

          C.just after line 7(that is,as the method returns)

          D.never in this method

          10:Math.round(-11.5)等於多少?

          A.-11

          B.-12

          C.-11.5

          D.none

          11:In the following pieces of code, which one will compile without any error?

          A.StringBuffer sb1 = "abcd";

          B.Boolean b = new Boolean("abcd");

          C.C: byte b = 255;

          D.float fl = 1.2;

          12:

          Give the following method:

          public void method( ){

          String a,b;

          a=new String(“hello world”);

          b=new String(“game over”);

          System.out.println(a+b+”ok”);

          a=null;

          a=b;

          System.out.println(a);

          }

          In the absence of compiler optimization, which is the earliest point the object a refered is definitely elibile to be garbage collection.

          Give the following method:

          public void method( ){

          String a,b;

          a=new String(“hello world”);

          b=new String(“game over”);

          System.out.println(a+b+”ok”);

          a=null;

          a=b;

          System.out.println(a);

          }

          In the absence of compiler optimization, which is the earliest point the object a refered is definitely elibile to be garbage collection.

          A.before line 5

          B.before line 6

          C.before line 7

          D.before line 9

          13:

          Give the following java class:

          public class Example{

          static int x[]=new int[15];

          public static void main(String args[]){

          System.out.println(x[5]);

          }

          }

          Which statement is corrected?

          Give the following java class:

          public class Example{

          static int x[]=new int[15];

          public static void main(String args[]){

          System.out.println(x[5]);

          }

          }

          Which statement is corrected?

          A.When compile, some error will occur.

          B.When run, some error will occur.

          C.Output is zero.

          D.Output is null.

          14:以下的C程序代碼片段運(yùn)行后C和d的值分別是多少

          Int a =1,b =2;

          Int c,d;

          c =(a&b)&&a;

          d =(a&&b)&a;

          A.0,0

          B.0,1

          C.1,0

          D.1,1

          簡(jiǎn)答題

          15:15個(gè)教徒和15 個(gè)非教徒在深海上遇險(xiǎn),必須將一半的人投入海中,其余的人才能幸免于難,于是想了一個(gè)辦法:30個(gè)人圍成一圓圈,從第一個(gè)人開始依次報(bào)數(shù),每數(shù)到第九個(gè)人就將他扔入大海,如此循環(huán)進(jìn)行直到僅余15個(gè)人為止。問怎樣排法,才能使每次投入大海的都是非教徒。

          16:構(gòu)造器Constructor是否可被override?

          17:簡(jiǎn)單介紹一下IOC的實(shí)現(xiàn)原理。(寫出代碼最好)

          18:說出數(shù)據(jù)連接池的.工作機(jī)制是什么?

          19:列出一些控制流程的方法;

          20:找出兩個(gè)字符串中最大子字符串,如"abractyeyt","dgdsaeactyey"的最大子串為"actyet"

          21:請(qǐng)寫一個(gè)java程序?qū)崿F(xiàn)數(shù)據(jù)庫(kù)緩沖池的功能?

          22:Tomcat里實(shí)現(xiàn)會(huì)話session復(fù)制,有那些方法?

          23:簡(jiǎn)單介紹JSP的標(biāo)記庫(kù)?

          24:hibernate的2級(jí)緩存有那些緩存策略?每種緩存策略的使用范圍?

          25:不用乘法或加法給一個(gè)數(shù)增加7倍。

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