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      1. 意法半導體筆試題 簡歷

        時間:2023-04-06 16:45:27 筆試題目 我要投稿
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        意法半導體筆試題 簡歷范文

        A Test for The C Programming Language

        意法半導體筆試題 簡歷范文

          I. History

          1. C was originally designed for and implemented on the (what) operating system on the DEC PDP-11, by (who) .

          2. The most recently approved ANSI/ISO C standard was issued in (when), and single line comments notation “//” is or isn’t a feature of C89.

          II. Syntax and Semantics 1.In a runtime C program, auto variables are stored in , staticvariables are stored in , and function parameters are stored in .

          a. stack b. heap c. neither stack nor heap

          2. The statement “extern int x;” is a , and the keyword extern is used during .

          a. variable declaration b. variable definition c. compilation time d. runtime

          3. There is a complicated declaration: void ( * signal (int, void(*)(int)) ) (int);If a statement “typedef void (*p) (int);” is given,please rewrite this complicated declaration.

          4. The following code is a segment of C program.

          ..........

          void func(int *p)

          {...........}

          ..........

          main()

          {

          int num=0;

          .........

          func(&num);

          ........

          }

          ..........

          Here, the function argument “&num” is passed .

          a. by value b. by reference

          III. Practice

          Create a tree, which has h (h>0) layers, and its each node has w(w>0) sub-nodes.Please complete the following incomplete solution.

          #include

          #include

          struct tree{

          char info;

          p_sub; //link to sub-nodes};

          // allocate memory and initiate

          void dnode ( struct tree* tmp )

          {

          = malloc( sizeof (struct tree) );

          = 0x41;

          = NULL;

          }

          struct tree *dtree (struct tree* subtree, int height, int width)

          {

          int i;

          if ( !subtree ) //if necessary, allocte memory for subtree

          denode(subtree);

          if ( height == 1 )

          return subtree;

          else if ( height == 2 ) {

          struct tree *leaf = NULL;

          for ( i=0; i

          denode ( );

          ;

          leaf = NULL;}

          return subtree;}

          else {

          for ( i=0; i

          }

          return subtree;

          }

          }

          main()

          {

          .........

          struct tree *root = NULL;

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